How to use Java 8 streams to find all values preceding a larger value?

By | March 24, 2023

To use Java 8 streams to find all values preceding a larger value in a list or array, you can use the filter() method along with a lambda expression that checks if each element is less than the larger value, and then use the collect() method to collect the filtered elements into a new list or array.

Here’s an example code snippet that demonstrates this approach:

List<Integer> numbers = Arrays.asList(5, 2, 8, 3, 9, 1);

int largerValue = 7;

List<Integer> precedingValues = numbers.stream()

        .filter(n -> n < largerValue)

        .collect(Collectors.toList());

System.out.println(precedingValues); // Output: [5, 2, 3, 1]

In the above example, we have a list of integers numbers and a larger value largerValue. We create a stream of numbers using the stream() method and then use the filter() method to keep only the elements that are less than largerValue. The lambda expression n -> n < largerValue checks if each element n is less than largerValue. Finally, we use the collect() method to collect the filtered elements into a new list using the Collectors.toList() method.

The resulting precedingValues list contains all the values in numbers that precede the larger value largerValue. In this example, the list contains the values [5, 2, 3, 1].

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